t^2-4.286t+2.449=0

Solution for t^2-4.286t+2.449=0 equation:

t^2-4.286t+2.449=0

a = 1; b = -4.286; c = +2.449;
Δ = b2-4ac
Δ = -4.2862-4·1·2.449
Δ = 8.573796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.286)-\sqrt{8.573796}}{2*1}=\frac{4.286-\sqrt{8.573796}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.286)+\sqrt{8.573796}}{2*1}=\frac{4.286+\sqrt{8.573796}}{2}
$